SOLUTION: How do I use the substitution method to solve the following system of eqautionsin which the solution consists of ordered pairs?
x^2 + y = 4
2x + y = 1
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x^2 + y = 4
2x + y = 1
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Question 46614This question is from textbook College Algebra by Blitzer
: How do I use the substitution method to solve the following system of eqautionsin which the solution consists of ordered pairs?
x^2 + y = 4
2x + y = 1 This question is from textbook College Algebra by Blitzer
You can put this solution on YOUR website! 2x + y = 1
also means:
y = -2x + 1
plug:
x^2 + y = 4
x^2 - 2x + 1 = 4
x^2 - 2x - 3 = 0
(x - 3)(x + 1) = 0
x = 3 and x = -1
plug:
y = -2x + 1
y = -2(3) + 1 = -5 so (3,-5)
y = -2x + 1
y = -2(-1) + 1 = 3 (-1,3)