You can put this solution on YOUR website! I just don't get this log32 (x) + log(2x)=1 Solve for x
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log[32x] + log[2x] = 1
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log[(32x)(2x)] = 1
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log[64x^2] = 1
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64x^2 = 10
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x^2 = 10/64
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x = (1/8)sqrt(10)
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Note: x cannot be negative as that would make log(2x) meaningless.
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Cheers,
Stan H.
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