SOLUTION: The length of a rectangle is 1 cm longer than its width. If the diagonal of the rectangle is 4 cm what are the dimensions (length and width) of the rectangle.
to start i get
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-> SOLUTION: The length of a rectangle is 1 cm longer than its width. If the diagonal of the rectangle is 4 cm what are the dimensions (length and width) of the rectangle.
to start i get
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Question 46608: The length of a rectangle is 1 cm longer than its width. If the diagonal of the rectangle is 4 cm what are the dimensions (length and width) of the rectangle.
to start i get
x^2 + (x+1)^2 = 4^2
x^2 + x^2 + 2x + 1 = 16
2x^2 + 2x - 15 = 0
x^2 + x - 7.5 = 0
This is where I can't go futher and I need to turn it in tonight.
Any help please and thank you. Answer by Nate(3500) (Show Source):
You can put this solution on YOUR website! x^2 + x^2 + 2x + 1 = 16
2x^2 + 2x = 15
x^2 + x = 7.5
(x + 1/2)^2 = 30/4 + 1/4 = 31/4
x + 1/2 = +-/2
x = -1/2 +- /2
You can not have a negative measurement, so your answer:
width = -1/2 + /2
length = 1/2 + /2
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