SOLUTION: Find the measure of an angle who supplement measures 39 more than twice its complement.
Like to know if I am setting up the equation properly?
Angle = x
Supplement = 180-x
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-> SOLUTION: Find the measure of an angle who supplement measures 39 more than twice its complement.
Like to know if I am setting up the equation properly?
Angle = x
Supplement = 180-x
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Question 466036: Find the measure of an angle who supplement measures 39 more than twice its complement.
Like to know if I am setting up the equation properly?
Angle = x
Supplement = 180-x
Complement = 90-x
180-x = 2(90-x)+39
180 = 219
x= 39
Can I also say the supplement is 141 degrees and the complement is 56 degrees even though the problem is not requesting to find them?
You can put this solution on YOUR website! You are correct in setting up the equation, and your final answer is correct; you probably typoed when you wrote "180 = 219" when it should be "180 = 219 - x." And the complement of 39 degrees is 90 - 39 = 51 degrees. You do not have to state the supplement or the complement for this problem.
Hi,
Find measure of an angle who supplement measures 39 more than twice its complement
you set it up very nicely!
180-x = 2(90-x)+39
180 = 219
x = 39, angle requested
CHECKING our Answer*** Finding Supp = 141 and Comp = 51 works nicely for checking,
Question only requested the original angle x however.
141 = 2*51 + 39 = 102 + 39 = 141
You can put this solution on YOUR website! Yes, you are setting up the equation right.
Just a minor correction...
x - 180 = 219
x = 39
The supplement is 141 degrees and the complement is 51 degrees.
You can put this solution on YOUR website! Find the measure of an angle who supplement measures 39 more than twice its complement.
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Angle = x
Supplement = 180-x
Complement = 90-x
180-x = 2(90-x)+39
---------- 180 does not equal 219. I think you're subtracting there.
180-x = 180 - 2x + 39
-x = -2x + 39
x = 39 degs
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Supp = 141, comp = 51