SOLUTION: In 1988, a dairy in Alberta, Canada, created a sundae with approximately 1 lb. of topping for every 83.2 lb. of ice cream. The total of the two ingredients weighed approximately 45

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: In 1988, a dairy in Alberta, Canada, created a sundae with approximately 1 lb. of topping for every 83.2 lb. of ice cream. The total of the two ingredients weighed approximately 45      Log On


   

Question 465748: In 1988, a dairy in Alberta, Canada, created a sundae with approximately 1 lb. of topping for every 83.2 lb. of ice cream. The total of the two ingredients weighed approximately 45,225 lb. To the nearest tenth of a pound, how many pounds of ice cream and how many pounds of topping were there?
I don't think I wrote the equation correctly.
2x + 83.2 = 45,225
83.2
-45.225
=37,975
I rounded it to 38
2x=38
2 2
x=19
But we all know this is incorrect.
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
for every 84.2 lbs of sundae, one lb is topping and 83.2 lb is ice cream

topping = (1 / 84.2) * 45225

ice cream = (83.2 / 84.2) * 45225