SOLUTION: Given the function f(x) = -x²+2x+3
(A)Determine the vertex,
(B)List the axis of symmetry,
(C)calculate the y-intercept,
(D)find an additional point on the graph, and
(E)g
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-> SOLUTION: Given the function f(x) = -x²+2x+3
(A)Determine the vertex,
(B)List the axis of symmetry,
(C)calculate the y-intercept,
(D)find an additional point on the graph, and
(E)g
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Question 465710: Given the function f(x) = -x²+2x+3
(A)Determine the vertex,
(B)List the axis of symmetry,
(C)calculate the y-intercept,
(D)find an additional point on the graph, and
(E)graph the function.
Please show all of your work.
I appreciate any help. Answer by ewatrrr(24785) (Show Source):
Hi
y = -x^2+2x+3 | y-intercept Pt(0,3)
Using the vertex form of a parabola, where(h,k) is the vertex
y = -x^2+2x+3 |completing the square
y = -[(x-1)^2 -1]+3
y = -(x-1)^2 +4 Vertex (1,4) a = -1 <0 Parbola opens downward, vertex is max pt
Line of symmetry is x = 1 and when y = 0 (x-1)^2 = 4 x = 3
