SOLUTION: Determine the value of k for which the system has no solutions x+y+3z=-1 x+2y-2z=-2 4x+12y+kz=-11

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Question 465640: Determine the value of k for which the system has no solutions
x+y+3z=-1
x+2y-2z=-2
4x+12y+kz=-11
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

x+y+3z=-1

x+2y-2z=-2

4x+12y+kz=-11

D=%28matrix%283%2C3%2C1%2C1%2C3%2C1%2C2%2C-2%2C4%2C12%2Ck%29%29

D=%28matrix%283%2C3%2Ca1%2Cb1%2Cc1%2Ca2%2Cb2%2Cc2%2Ca3%2Cb3%2Cc3%29%29 

D = a1(b2c3-c2b3) - b1(a2c3-c2a3) + c1(a2b3-b2a3) 

 0 = (2k+24)-(k+8) + 3(4)

-28 = k