SOLUTION: Solve the equations {{{(3)^x}}}.{{{(9)^(2y) = 1}}},
{{{(5)^(3x) (25)^y = 1/125}}}
*Please answer as soon as possible bro :)
Algebra ->
Systems-of-equations
-> SOLUTION: Solve the equations {{{(3)^x}}}.{{{(9)^(2y) = 1}}},
{{{(5)^(3x) (25)^y = 1/125}}}
*Please answer as soon as possible bro :)
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5 ^(3x+2y) = 5^(-3)
so, 3x+2y= -3
now, multiply the second equation by 2 and subtract from first equation,
x -6x = 0 - (-6)
=> -5x = 6
so, x = -6/5
and y = 6/20
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