Question 465532: log2x+1/2log2(x+2)=2
solve for x
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! log2x+1/2log2(x+2)=2
solve for x
...
log2x+1/2log2(x+2)=2
rewrite as single log
log2[(x)(x+2)^1/2]=2
convert to exponential form: (base(2) raised to log of number(2)=number[(x)(x+2)^1/2]
2^2=(x)(x+2)^1/2=4
square both sides
x^2(x+2)=16
x^3+2x^2-16=0
..
Don't know how to solve this equation algebriacally, but my graphing calculator shows there is one real root, x=2
|
|
|
