SOLUTION: I need to solve the following:
{{{ e^x }}}-{{{ 1/e^x }}}=2
*I had to write this differently because of the formula plotting system (the second part is really e to the -x inst
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-> SOLUTION: I need to solve the following:
{{{ e^x }}}-{{{ 1/e^x }}}=2
*I had to write this differently because of the formula plotting system (the second part is really e to the -x inst
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Question 465502: I need to solve the following:
-=2
*I had to write this differently because of the formula plotting system (the second part is really e to the -x instead of 1/e^x).
So I believe from here you subtract 2 from both sides and end up with everything equal to zero, and then you would let u=, so that you have u-(1/u)-2=0. Then I get confused as to how to solve this by using the quadratic formula, because I don't know what b=? . That is really all I am confused on, assuming I'm going about this the right way in the first place.
I hope I've explained that well. Thanks!
Jessica Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! -=2
Multiply thru by e^x
Sub u for e^x
u = 1 +/- sqrt(2)
x = ln(1 +/- sqrt(2))
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PS hyp cos(x) =
hyp sin(x) =
