SOLUTION: I have a quick clarifying question: I solved a problem to where the two results are e^x= 1/3 or e^x= -2. I believe that you can't deal with the -2 because it's negative, but th

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: I have a quick clarifying question: I solved a problem to where the two results are e^x= 1/3 or e^x= -2. I believe that you can't deal with the -2 because it's negative, but th      Log On


   



Question 465374: I have a quick clarifying question:
I solved a problem to where the two results are e^x= 1/3 or e^x= -2. I believe that you can't deal with the -2 because it's negative, but then my answer key is telling me that x= -ln 3. I guess this is because ln 1/3 is ln 1 - ln 3, but wouldn't that be -ln 2. I hope that makes sense to you, because I am confused. I guess I just need a little brush-up on some properties here.
Thanks,
Jessica

Answer by richard1234(7193) About Me  (Show Source):
You can put this solution on YOUR website!
ln 1 - ln 3 is actually ln 1/3 (the property is ln a - ln b = ln (a/b)). Also, there is no real solution x such that e^x = -2, because e^x is always positive for real x.

Update: Remember ln 1 - ln 3 = ln 1/3. Since ln 1 = 0, we have -ln 3 = ln 1/3.