SOLUTION: x^2 + 10x - 47 = 0 round to the nearest thousandth
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Question 46518
:
x^2 + 10x - 47 = 0
round to the nearest thousandth
Answer by
checkley71(8403)
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x~2+10x-47 or (x-3.485)(x+13.485) or x=3.485 & x=-13.485
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