|
Question 465135: Help me please! Plot the x and y intercepts and sketch the line.
3x + 5y + 15 = 0
Answer by algebrahouse.com(1659) (Show Source):
You can put this solution on YOUR website! "Help me please! Plot the x and y intercepts and sketch the line.
3x + 5y + 15 = 0"
To find the x-intercept (where it crosses the x-axis), put 0 in for y:
3x + 5y + 15 = 0
3x + 5(0) + 15 = 0 {substituted 0 in for y}
3x + 15 = 0 {multiplied 5 by 0}
3x = -15 {subtracted 15 from both sides}
x = -5 {divided both sides by 3}
x-intercept = -5.....coordinates are (-5,0) where it crosses the x-axis
To find the y-intercept (where it crosses the y-axis), put 0 in for x:
3x + 5y + 15 = 0
3(0) + 5y + 15 = 0 {substituted 0 in for x}
5y + 15 = 0 {multiplied 3 by 0}
5y = -15 {subtracted 15 form both sides}
y = -3 {divided both sides by 5}
y-intercept = -3.....coordinates are (0,-3), where it crosses the y-axis
To graph:
- put a point on (-5,0) {the x-intercept}
- put a point on (0,-3) {the y-intercept}
- draw a line through the two points
For more help from me, visit: www.algebrahouse.com
|
|
|
| |