SOLUTION: What is the sum of all the positive 3-digit whole numbers with even digits only?

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Question 465132: What is the sum of all the positive 3-digit whole numbers with even digits only?
Answer by robertb(5830) About Me  (Show Source):
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Sum of all units digits: 20*(0+2+4+6+8) = 20*20 = 400
Sum of all tens digits: 10*(0+2+4+6+8)*20 = 4000
Sum of all hundreds digits: 100*(2+4+6+8)*25 = 50000
Total: = 400 + 4000 + 50000 = 54,400.