Hi,
Using the vertex form of a parabola,
where(h,k) is the vertex
f(x) =2x^2-12x+13 | Completing square to put into vertex form
f(x) = 2[(x-3)^2-9]+13
f(x) = 2(x-3)^2 - 5 |V(3,-5), a = 2 > 0, parabola opens upward, vertex a min Pt
x = 3, line of symmetry
