SOLUTION: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function. f(x) = -4(x+3)^2+6

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Question 464951: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function. f(x) = -4(x+3)^2+6
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi, Inanswer to Your question:  Yes, f(x) maximum value is the 6.

Using the vertex form of a parabola, y=a%28x-h%29%5E2+%2Bk where(h,k) is the vertex

f(x) = -4(x+3)^2+6 | highlight%28V%28-3%2C6%29%29, a = -4<0, parabola opens downward, vertex a max Pt

x = -3, line of symmetry