SOLUTION: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function. f(x) = -x^2+8x+6

Algebra ->  Equations -> SOLUTION: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function. f(x) = -x^2+8x+6      Log On


   

Question 464948: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function. f(x) = -x^2+8x+6
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

Using the vertex form of a parabola, y=a%28x-h%29%5E2+%2Bk where(h,k) is the vertex

f(x) = -x^2+8x+6 | Completing square to put into vertex form

f(x) = -[(x-4)^2-16]+6

f(x) = -(x-4)^2 + 22 |V(4,22), a = -1 <0 ,parabola opens downward, vertex a max Pt

x = 4, line of symmetry