SOLUTION: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function. f(x) = 6-x^2

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function. f(x) = 6-x^2      Log On


   

Question 464938: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function. f(x) = 6-x^2
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

Using the vertex form of a parabola, y=a%28x-h%29%5E2+%2Bk where(h,k) is the vertex

f(x) = -x^2 + 6  |Vertex(0,highlight%286%29) Maximum PT, parabola opens downward: a = -1 < 0

Line of symmetry is the y-axis