SOLUTION: When the number 540 is written as a product of it's prime factos in the from a^2b^3c, what is the numerical value of a+b+c?
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-> SOLUTION: When the number 540 is written as a product of it's prime factos in the from a^2b^3c, what is the numerical value of a+b+c?
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Question 464755: When the number 540 is written as a product of it's prime factos in the from a^2b^3c, what is the numerical value of a+b+c? Answer by richard1234(7193) (Show Source):
You can put this solution on YOUR website! 540 is equal to 5*(2^2)*(3^3). This implies a = 2, b = 3, c = 5 (match up the exponents with the correct bases). Hence, a+b+c = 10.
