SOLUTION: thw sum of four consectutive integers in 62. what are the four integers?

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Question 464728: thw sum of four consectutive integers in 62. what are the four integers?

Found 2 solutions by jorel1380, algebrahouse.com:
Answer by jorel1380(3719) About Me  (Show Source):
You can put this solution on YOUR website!
n+n+1+n+2+n+3=62
4n+6=62
4n=56
n=14
The integers are 14,15,16, and 17..

Answer by algebrahouse.com(1659) About Me  (Show Source):
You can put this solution on YOUR website!
"the sum of four consectutive integers in 62. what are the four integers?"

x = 1st integer
x + 1 = 2nd integer
x + 2 = 3rd integer
x + 3 = 4th integer

x + x + 1 + x + 2 + x + 3 = 62 {the sum of four consecutive integers is 62}
4x + 6 = 62 {combined like terms}
4x = 56 {subtracted 6 from both sides}
x = 14 {divided both sides by 4}
x + 1 = 15
x + 2 = 16
x + 3 = 17

14, 15, 16, and 17 are the four consecutive integers

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