SOLUTION: Solve using Cramer's Rule. x + 3y + 5z = 6 2x - 4y + 6z = 14 9x - 6y + 3z = 3 I came up with (1,-2,1) but Cramers rule confuses me so I don't know if I did it right

Algebra ->  Matrices-and-determiminant -> SOLUTION: Solve using Cramer's Rule. x + 3y + 5z = 6 2x - 4y + 6z = 14 9x - 6y + 3z = 3 I came up with (1,-2,1) but Cramers rule confuses me so I don't know if I did it right      Log On


   



Question 464642: Solve using Cramer's Rule.
x + 3y + 5z = 6
2x - 4y + 6z = 14
9x - 6y + 3z = 3
I came up with (1,-2,1) but Cramers rule confuses me so I don't know if I did it right

Found 3 solutions by MathLover1, Alan3354, Edwin McCravy:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

Solved by pluggable solver: Using Cramer's Rule to Solve Systems with 3 variables



system%281%2Ax%2B3%2Ay%2B5%2Az=6%2C2%2Ax%2B-4%2Ay%2B6%2Az=14%2C9%2Ax%2B-6%2Ay%2B3%2Az=3%29



First let A=%28matrix%283%2C3%2C1%2C3%2C5%2C2%2C-4%2C6%2C9%2C-6%2C3%29%29. This is the matrix formed by the coefficients of the given system of equations.


Take note that the right hand values of the system are 6, 14, and 3 and they are highlighted here:




These values are important as they will be used to replace the columns of the matrix A.




Now let's calculate the the determinant of the matrix A to get abs%28A%29=288. To save space, I'm not showing the calculations for the determinant. However, if you need help with calculating the determinant of the matrix A, check out this solver.



Notation note: abs%28A%29 denotes the determinant of the matrix A.



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Now replace the first column of A (that corresponds to the variable 'x') with the values that form the right hand side of the system of equations. We will denote this new matrix A%5Bx%5D (since we're replacing the 'x' column so to speak).






Now compute the determinant of A%5Bx%5D to get abs%28A%5Bx%5D%29=-288. Again, as a space saver, I didn't include the calculations of the determinant. Check out this solver to see how to find this determinant.



To find the first solution, simply divide the determinant of A%5Bx%5D by the determinant of A to get: x=%28abs%28A%5Bx%5D%29%29%2F%28abs%28A%29%29=%28-288%29%2F%28288%29=-1



So the first solution is x=-1




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We'll follow the same basic idea to find the other two solutions. Let's reset by letting A=%28matrix%283%2C3%2C1%2C3%2C5%2C2%2C-4%2C6%2C9%2C-6%2C3%29%29 again (this is the coefficient matrix).




Now replace the second column of A (that corresponds to the variable 'y') with the values that form the right hand side of the system of equations. We will denote this new matrix A%5By%5D (since we're replacing the 'y' column in a way).






Now compute the determinant of A%5By%5D to get abs%28A%5By%5D%29=-288.



To find the second solution, divide the determinant of A%5By%5D by the determinant of A to get: y=%28abs%28A%5By%5D%29%29%2F%28abs%28A%29%29=%28-288%29%2F%28288%29=-1



So the second solution is y=-1




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Let's reset again by letting A=%28matrix%283%2C3%2C1%2C3%2C5%2C2%2C-4%2C6%2C9%2C-6%2C3%29%29 which is the coefficient matrix.



Replace the third column of A (that corresponds to the variable 'z') with the values that form the right hand side of the system of equations. We will denote this new matrix A%5Bz%5D






Now compute the determinant of A%5Bz%5D to get abs%28A%5Bz%5D%29=576.



To find the third solution, divide the determinant of A%5Bz%5D by the determinant of A to get: z=%28abs%28A%5Bz%5D%29%29%2F%28abs%28A%29%29=%28576%29%2F%28288%29=2



So the third solution is z=2




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Final Answer:




So the three solutions are x=-1, y=-1, and z=2 giving the ordered triple (-1, -1, 2)




Note: there is a lot of work that is hidden in finding the determinants. Take a look at this 3x3 Determinant Solver to see how to get each determinant.



Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
http://www.analyzemath.com/Calculators/Calculator_syst_eq.html

Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
 x + 3y + 5z = 6
2x - 4y + 6z = 14
9x - 6y + 3z = 3

Sorry, the solution is (-1,-1,2)

 







x=D%5Bx%5D%2FD+=+%28-288%29%2F288+=+-1

y=D%5By%5D%2FD+=+%28-288%29%2F288+=+-1

z=D%5Bx%5D%2FD+=+%28576%29%2F288+=+2

So (x,y,z) = (-1,-1,2)

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Checking:
system%28x+%2B+3y+%2B+5z+=+6%2C%0D%0A2x+-+4y+%2B+6z+=+14%2C%0D%0A9x+-+6y+%2B+3z+=+3%29

becomes:



system%28-1+-+3+%2B+10+=+6%2C%0D%0A-2+%2B+4+%2B+12+=+14%2C%0D%0A-9+%2B+6+%2B+6+=+3%29

system%286+=+6%2C%0D%0A14+=+14%2C%0D%0A-3+=+3%29

Edwin