SOLUTION: A container is filled by 2 pipes ( one small & one big ) in 12 mins.
If the smaller pipe can fill it alone in 10 mins more than the larger pipe, find
the time taken for the smal
Algebra ->
Volume
-> SOLUTION: A container is filled by 2 pipes ( one small & one big ) in 12 mins.
If the smaller pipe can fill it alone in 10 mins more than the larger pipe, find
the time taken for the smal
Log On
Question 464459: A container is filled by 2 pipes ( one small & one big ) in 12 mins.
If the smaller pipe can fill it alone in 10 mins more than the larger pipe, find
the time taken for the smaller pipe to fill the container alone. Answer by jorel1380(3719) (Show Source):
You can put this solution on YOUR website! 1/t+1/t+10=1/12
12(t+10)+12t=t(t+10)
12t+120+12t=t2+10t
t2-14t-120=0
(t-20)(t+6)=0
t=20 or -6
Throwing out the negative answer we get the larger pipe taking 20 minutes, and the smaller pipe taking t+10, or 30 minutes..
