SOLUTION: If a rectangle has a total perimeter of 288 feet and the length is 7 times it's width,what are the dimensions?

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Question 463997: If a rectangle has a total perimeter of 288 feet and the length is 7 times it's width,what are the dimensions?
Answer by algebrahouse.com(1659) About Me  (Show Source):
You can put this solution on YOUR website!
x = width
7x = length

Perimeter of a rectangle is 2(width) + 2(length)

2x + 2(7x) = 288 {perimeter is 2(width) + 2(length)}
2x + 14x = 288 {multiplied 2 by 7x}
16x = 288 {combined like terms}
x = 18 {divided both sides by 16}
7x = 126 {substituted 18, in for x, into 7x}

width = 18 ft and length = 126 ft

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