Question 463994: I have to graph the following equation of the two periods of a tangent. The problem is y= 2 tan x/4. Please help me I am completly lost!
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! I have to graph the following equation of the two periods of a tangent. The problem is y= 2 tan x/4.
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Standard form of the Tangent function: y=A(Bx-C), with period=π/B, Phase-shift=C/B, A=multiplier which stretches the curve vertically
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For given tangent function: y=2 tan x/4
B=1/4
Period=π/B=π/(1/4)=4π
1/4 Period=π
C=0
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Graphing:
On the x-axis, starting from 0, make tick marks at π, 2π, 3π, 4π, 5π, 6π, 7π, and 8π.
This covers 2 periods of the given tan function.
Draw vertical asymptotes at x=2π and x=6π
At x=π & 5π, y=2
At x=3π & 7π, y=-2
You now have the following points to plot the graph for y=2 tan x/4:
(0,0), (π,2), (2π, ud) (3π,-2), (4π,0), (5π,2), (6π,ud),(7π,-2), (8π,0) (ud=vertical asymptotes)
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