SOLUTION: p(x)=-2x^2+39x-132 find the maximun and minimum i belive the vertex is (9.75,566.65)

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: p(x)=-2x^2+39x-132 find the maximun and minimum i belive the vertex is (9.75,566.65)      Log On


   

Question 463888: p(x)=-2x^2+39x-132 find the maximun and minimum i belive the vertex is (9.75,566.65)
Answer by richard1234(7193) About Me  (Show Source):
You can put this solution on YOUR website!
I assumed you meant -2x^2 + 39x - 132 so I changed it.

The x-coordinate of the vertex occurs at -39/(2*-2) = 9.75. Also, p(39/4) = 58.125, so the coordinate of the vertex is (9.75, 58.125).

This vertex is the maximum of the parabola, because it opens downward. There is no minimum because the parabola goes to negative infinity as x gets really large (or small).

graph%28300%2C300%2C-150%2C150%2C+-150%2C+150%2C+-2x%5E2+%2B+39x+-+132%29