SOLUTION: Solve the equation:
8x^2 + 5x - 4 = 2x^2 - 8x +1
First I subtracted to get 0 on one side of the equation
6x^2 + 13x -5 =0
I couldn't factor that to solve the problem. Wh
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-> SOLUTION: Solve the equation:
8x^2 + 5x - 4 = 2x^2 - 8x +1
First I subtracted to get 0 on one side of the equation
6x^2 + 13x -5 =0
I couldn't factor that to solve the problem. Wh
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Question 463705: Solve the equation:
8x^2 + 5x - 4 = 2x^2 - 8x +1
First I subtracted to get 0 on one side of the equation
6x^2 + 13x -5 =0
I couldn't factor that to solve the problem. What do I do? Answer by algebrahouse.com(1659) (Show Source):
You can put this solution on YOUR website! 8x^2 + 5x - 4 = 2x^2 - 8x +1
6x^2 + 13x -5 =0
(3x - 1)(2x + 5) = 0 {factored into two binomials}
3x - 1 = 0 or 2x + 5 = 0 {set each factor equal to 0}
3x = 1 or 2x = -5 {added 1 and subtracted 5, respectively}
x = 1/3 or x = -5/2 {divided by 3 and 2, respectively}
If you didn't factor, the quadratic formula would've worked also.
