SOLUTION: Let me try to solve your system of equation 4x + 4y = 16 and 2x + y = 10 using the elimination method. �Multiply the equation 2x + y = 10 by -2; -4x

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Question 463648: Let me try to solve your system of equation 4x + 4y = 16 and 2x + y = 10 using the elimination method.
�Multiply the equation 2x + y = 10 by -2; -4x - 2y = -10.
�Add the equation 4x + 4y = 16 and the equation -4x - 2y = -10 together; 2y = 6.
�Isolate the variable y by dividing both sides of the equation by 2; y = 3.
Can anyone tell us why I multiplied the equation 2x + y = 10 by -2?
is this correct so far? please help!!
Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website!
Let me try to solve your system of equation 4x + 4y = 16 and 2x + y = 10 using the elimination method.
�Multiply the equation 2x + y = 10 by -2; -4x - 2y = -10.
�Add the equation
4x + 4y = 16 and the equation
-4x - 2y = -10 together;
-----------------
2y = 6.
�Isolate the variable y by dividing both sides of the equation by 2; y = 3.
Can anyone tell us why I multiplied the equation 2x + y = 10 by -2?
To get the coefficients of x to match.
--------------
is this correct so far? please help!!
It's correct, y = 3
-------------
Sub for y in 2x + y = 10
2x + 3 = 10
2x = 7
x = 3.5 or 7/2
That's all

SOLUTION: Let me try to solve your system of equation 4x + 4y = 16 and 2x + y = 10 using the elimination method. �Multiply the equation 2x + y = 10 by -2; -4x - 2y = -10. �Add the equatio