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Question 463608: What is the equation of a line that passes through the point (3, -1) and is perpendicular to a line with a slope of 3/4 ?
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! What is the equation of a line that passes through the point (3, -1) and is perpendicular to a line with a slope of 3/4
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Standard form for a straight line: y=mx+b, m=slope, b=y-intercept
Slope of given line=negative reciprocal of the slope of perpendicular line=-4/3
y=(-4/3)x+b
solving for b using (x,y) coordinates of given point (3,-1)
-1=(-4/3)3+b
-1=-4+b
b=3
Equation of line:
y=-4x/3+3
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