Question 463552: find the two consecutive odd integers such that the lesser is added to twice the greater, the result is 24 more than the greater interger
Answer by algebrahouse.com(1659)   (Show Source):
You can put this solution on YOUR website! "find the two consecutive odd integers such that the lesser is added to twice the greater, the result is 24 more than the greater interger"
x = 1st odd integer
x + 2 = 2nd odd integer {odd integers increase by 2 each time}
x + 2(x + 2) = x + 2 + 24 {the lesser is added to twice greater, result is 24 more than greater}
x + 2x + 4 = x + 26 {used distributive property on left, combined like terms on right}
3x + 4 = x + 26 {combined like terms on left}
3x = x + 22 {subtracted 4 from both sides}
2x = 22 {subtracted x from both sides}
x = 11 {divided both sides by 2}
x + 2 = 13 {substituted 11, in for x, into x + 2}
11 and 13 are the two odd integers
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