SOLUTION: The perimeter of a rectangle is 60 metres. If its length is twice its breadth, then its area is?

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Question 463323: The perimeter of a rectangle is 60 metres. If its length is twice its breadth, then its area is?
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

The perimeter of a rectangle is P=60+m.
If its length L is twice its width W, then its area A is:

A=L%2AW....since L=2W area will be
A=2W%2AW
A=2W%5E2.......now use P to find W
P=2%28L%2BW%29
60+m=2%282W%2BW%29
cross%2860%2930+m=cross%282%29%282W%2BW%29
30+m=3W
30+m%2F3=W
10+m=W
now find L
L=2W...->...L=20m

A=2W%5E2
A=2%2A%2810m%29%5E2
A=2%28100m%5E2%29
A=200m%5E2
or
A=L%2AW
A=20m%2A10m
A=200m%5E2