SOLUTION: x^3-8x^2+11x+20 i am to find the factorization of this polynomial

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Question 462870: x^3-8x^2+11x+20
i am to find the factorization of this polynomial

Found 2 solutions by MathLover1, Edwin McCravy:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

x%5E3-8x%5E2%2B11x%2B20......replace -8x%5E2 with -5x%5E2-4x%5E2%2Bx%5E2 and 11x with 20x-5x-4x

x%5E3-5x%5E2-4x%5E2%2Bx%5E2%2B20x-5x-4x%2B20.....group

%28x%5E3-5x%5E2%29-%284x%5E2-20x%29%2B%28x%5E2-5x%29-%284x-20%29

x%5E2%28x-5%29-4x%28x-5%29%2Bx%28x-5%29-4%28x-5%29

%28x%5E2-4x%2Bx-4%29%28x-5%29

%28%28x%5E2-4x%29%2B%28x-4%29%29%28x-5%29

%28x%28x-4%29%2B%28x-4%29%29%28x-5%29

%28x%2B1%29%28x-4%29%28x-5%29

Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!

x³ - 8x² + 11x + 20

The possible rational zeros are ± the factors of 20:

±1, ±2, ±4, ±5, ±10, ±20

We will start out trying 1

1 | 1 -8  11  20
  |    1  -7   4 
    1 -7   4  24

No, 1 is not a zero because we got a remainder
of 24, not 0.  So we will try -1

-1 | 1 -8  11  20
   |   -1   9 -20 
     1 -9  20   0

This time we got a zero remainder, so we have
factored 
 
x³ - 8x² + 11x + 20

as

(x + 1)(x² - 9x + 20)

The expression in the second parentheses will
factor again

(x + 1)(x - 4)(x - 5)

That's it.

Edwin