SOLUTION: Evaluate the expression: t^logt(5x^2 - 2x+7)

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Question 462322: Evaluate the expression:
t^logt(5x^2 - 2x+7)
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Evaluate the expression:
t^logt(5x^2 - 2x+7)
..
Using the definition of a logarithm: (exponential form)
Base(t) raised to the log of the number(logt(5x^2 - 2x+7)=number(5x^2 - 2x+7)
so, t^logt(5x^2 - 2x+7)=5x^2 - 2x+7