SOLUTION: y^4+24y^2-25=0 Solve the polynomial equation by indicating first set of solutions and the second set.

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Question 462173: y^4+24y^2-25=0 Solve the polynomial equation by indicating first set of solutions and the second set.
Answer by algebrahouse.com(1659) About Me  (Show Source):
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y^4 + 24y^2 - 25 = 0
(y² + 25)(y² - 1) = 0 {factored into two binomials}
y² + 25 = 0 or y² - 1 = 0 {set each factor equal to 0}
y² = -25 or y² = 1 {subtracted 25 and added 1 respectively}
y = ±√-25 or y = ±√1 {took square root of both sides in each equation}
y = ±√-1 √25 or y = ±1 {broke -25 into 25 and -1 and evaluated √1 to be 1}
y = ±5i or y = ±1 {evaluated √-1 to be i}
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