SOLUTION: hi am stuck on a question on theory of numbers a, b, c, c, are four unequal positive numbers. by using the theorem (if a=b, then a+c=b+c and ac=bc) and considering the first pai

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Question 461625: hi am stuck on a question on theory of numbers
a, b, c, c, are four unequal positive numbers. by using the theorem (if a=b, then a+c=b+c and ac=bc) and considering the first pair of numbers 1/2(a+b) and 1/2(c+d) and then separately, the pairs a,b and c,d prove that
1/4(a+b+c+d)>(abcd)^1/4
Deduce by considering the four unequal numbers a,b,c and 1/3(a+b+c)that
1/3(a+b+c)>(abc)^1/3
what happens to the last inequality (i) if a=b=c
(ii)if a=b≠c?
suggest a generalization of the results proved above?
Phew this is one of the toughest questions i have ever come across?

Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!

Since the inequality we are to prove for the letters
representing unequal positive numbers:


and one of the other parts is



Then we might suppose that the first thing we need to
prove is that for any different positive numbers a and b 



The technique I will use is to assume that it is false,
and then reach a contradiction.  

So for contradiction we will assume that for 0%3Ea%3C%3Eb%3E0,  
 


Multiply both sides by 2



Square both sides:





Subtract 4ab from both sides:



Factor the left side:

drawing%28175%2C60%2C0%2C10%2C-10%2C7%2C+locate%281%2C3%2C%0D%0A%28a-b%29%5E2%3C=0+%29+%29

This is false since the left side is positive,
since a and b are different.

So we have reached a contradiction and therefore
we have proved that 



Note that the two sides are equal if a=b.

We have also proved by letting a=c and b=d.
that for 0%3Ec%3C%3Ed%3E0 



Down below we will need this for positive x,y: 



with equality holding if and only if x=y.

We do this to avoid getting letters confused.


--------------------------------

Next we will prove that for a,b,c,d > 0, all different,



We start with




Multiply both sides by 2, and we have:




Add the two inequalities:



Factor out 2 on the right



Make the left side into the left side of what
we have to prove by multiplying thru hy 1/4



Now we will show that the right side is greater than or equal
to drawing%28100%2C60%2C0%2C10%2C-10%2C7%2C+locate%281%2C3%2C+%28abcd%29%5E%281%2F4%29%29+%29

We recall from above that for positive x, y,



with equality holding if and only if x=y

We let x = drawing%28100%2C60%2C0%2C10%2C-10%2C7%2C+locate%281%2C3%2C+%28ab%29%5E%281%2F2%29%29+%29
and y = drawing%28100%2C60%2C0%2C10%2C-10%2C7%2C+locate%281%2C3%2C+%28cd%29%5E%281%2F2%29%29+%29





[Notice that we had to include the possibility of equality 
since even though a,b,c,d are all distinct, that does not
guarantee that drawing%28100%2C60%2C0%2C10%2C-10%2C7%2C+locate%281%2C3%2C+%28ab%29%5E%281%2F2%29%29+%29
 and drawing%28100%2C60%2C0%2C10%2C-10%2C7%2C+locate%281%2C3%2C+%28cd%29%5E%281%2F2%29%29+%29
 are distinct, e.g. if a=1,b=6,c=2,d=3, they are not distinct.]

So we have proved:



which is what we had to proved.

---------------------------------------

For different positive a,b,c, we need to prove



Sorry, I haven't figured out how to do this one yet.

------------------------------------

The generalization.  If all ai are 
positive numbers, then



and equality holds only when all the ai are equal.

Edwin