SOLUTION: Find two consecutive integers such that the sum of 2 times the first integer and 7 times second integer is 88.

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Question 46150: Find two consecutive integers such that the sum of 2 times the first integer and 7 times second integer is 88.
Answer by vihits13(20) About Me  (Show Source):
You can put this solution on YOUR website!
since they have to be consecutive lets say the numbers are n and n+1.
so, 2(n)+ 7(n+1)= 88
2n + 7n+7 = 88
9n+7=88
9n=81
n=9
so the first integer is 9 and the second integer is 10.