Question 461372: Please help.
I have to find the coordinates of the vertex of parabola y = -2 (x + 30)^2 + 8
and find the axis of symmetry of the graph y = 3(x-7)^2 +2
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! I have to find the coordinates of the vertex of parabola y = -2 (x + 30)^2 + 8
and find the axis of symmetry of the graph y = 3(x-7)^2 +2
...
Standard form for parabola: y=A(x-h)^2+k, with (h,k) being the (x,y) coordinates of the vertex
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For given equation: y=-2(x+30)^2+8
vertex is at (-30,8)
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For given equation: y=3(x-7)^2 +2
This is a parabola that opens upwards with vertex at (7,2)
So its axis of symmetry is x=7
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