Question 461190: A confidence interval estimate for the population mean is given to be (46.66, 54.74). If the standard deviation is 11.822 and the sample size is 57, answer each of the following (show all work):
(A) Determine the maximum error of the estimate, E.
(B) Determine the confidence level used for the given confidence interval
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! A confidence interval estimate for the population mean is given to be
(46.66, 54.74).
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If the standard deviation is 11.822 and the sample size is 57, answer each of the following (show all work):
(A) Determine the maximum error of the estimate, E.
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Fact: The width of the Confidence interval is ALWAYS 2*ME
2*ME = (54.74-46.66) = 8.08
ME = 4.04
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(B) Determine the confidence level used for the given confidence interval
ME = zs/Sqrt(n)
4.04 = z*11.822/sqrt(57)
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z = 2.5
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Confidence level = 1 - 2*P(z > 2.5) = 1 - 1.24% = 98.76%
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Cheers,
Stan H.
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