SOLUTION: Can someone please help me with this question...i have a test tomorrow and I dont know how to get an answer for this question..
Angel kayaks 20km upstream in 3hr and returns in
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-> SOLUTION: Can someone please help me with this question...i have a test tomorrow and I dont know how to get an answer for this question..
Angel kayaks 20km upstream in 3hr and returns in
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Question 461151: Can someone please help me with this question...i have a test tomorrow and I dont know how to get an answer for this question..
Angel kayaks 20km upstream in 3hr and returns in 1.5hr. how fast is the stream flowing and how fast does angel paddle in still water? Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! boat speed= x mph
current speed= y mph
with stream speed= (x+y) mph
against stream speed = (x-y) mph
d= 20
20/ (x+y) = 1.5
divide by 1.5
13.33 / (x+y) = 1
(x+y) = 13.33 ............1
d= 20
60/(x-y) = 3
divide by 3
6.67 /(x-y) = 3
x - y = 6.67 .............2
add up (1) & (2)
2 x = 20
/ 2
x= 10 mph speed of boat in still water
plug value of x in (1)
we get y= 3.33 mph speed of current
