a)find a linear model using the years 0 and 4
Find the equation of a line through the points
(0,11.807) and (4,29.349)
m =
then use
y - y1 = m(x - x1)
y - 11.807 = 4.3855(x - 0)
y - 11.807 = 4.3855x
y = 4.3855x + 11.807
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b)find a linear model using the graphing calculator.
press CLEAR
press STAT
press the right arrow key to highlight CALC
press 4
You will see
LinReg(ax+b)
Press ENTER
You will see
LinReg
y=ax+b
a=5.6524
b=8.731
rē=.9861609225
r=.9930563541
The equation of the line is y = 5.6524x + 8.731
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c)what is the correlation coefficient?
That's the value of r, which is r=.9930563541
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d)use your model to predict the numbers for 2010.
1995, 0
1997, 2
1999, 4
2001, 6
2003, 8
2005, 10
Extend this list by 2's:
2007, 12
2009, 14
2011, 16
Since 2010 is halfway between 2009, 14 and 2011 16,
we must have 2010 as 15.
So we substitute 15 for x in the formula:
y = 5.6524x + 8.731
y = 5.6524(15) + 8.731
y = 93.517
Edwin