SOLUTION: A doctor says that greater than 20% of US adults chew tobacco. In a random sample of 170 US adults, 15.5% say they chew tobacco. At alpha = .05, is there enough evidence to reject
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Question 460435: A doctor says that greater than 20% of US adults chew tobacco. In a random sample of 170 US adults, 15.5% say they chew tobacco. At alpha = .05, is there enough evidence to reject the doctor's claim?
null: > or equal to .20
alternative: < .20
Left tailed test Answer by edjones(8007) (Show Source):
You can put this solution on YOUR website! H[o]:>.20
n=170, P=.155 Q=.845
z=(.155-.200)/sqrt((.155*.845)/170)=-.045/.028=-1.62
Since -1.62>-1.64 (the low bound of .05), we cannot reject the null hypothesis.
.
Ed
