SOLUTION: (4-2i)^2
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Question 46033
:
(4-2i)^2
Answer by
fractalier(6550)
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Okay, we FOIL it and get
(4-2i)^2 =
(4 - 2i)(4 - 2i) =
16 - 8i - 8i + 4i^2 =
16 -16i - 4 =
12 - 16i