SOLUTION: Hello there, I am almost done with solvong a question but need a little more help. The equation is x^2-4x+2xy-8y and I am at the step of x(x-4)+2y(x-4) and I am unsure how to get t
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-> SOLUTION: Hello there, I am almost done with solvong a question but need a little more help. The equation is x^2-4x+2xy-8y and I am at the step of x(x-4)+2y(x-4) and I am unsure how to get t
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Question 46026: Hello there, I am almost done with solvong a question but need a little more help. The equation is x^2-4x+2xy-8y and I am at the step of x(x-4)+2y(x-4) and I am unsure how to get to the answer of (x-4)(x+2y) can anyone help? Answer by fractalier(6550) (Show Source):
You can put this solution on YOUR website! Yes, you are almost there...notice from
x(x-4)+2y(x-4)
there is a common factor in each term...that is, the (x-4)...
you can pull it out in front just like any other factor and get
(x-4) times what's left from each term...so we get
(x-4)(x+2y)
