You can put this solution on YOUR website! what is the maximum possible area of a rectangle with a perimeter of 14
-----
Perimeter = 2(L + W) = 14
L+W = 7
----
L = 7-W
---------
Area = LW
Solve: (7-W)W = maximum Area
----
A = 7W-W^2
----
Maximum A occurs when W = -b/(2a) = -7/(2*-1) = 3.5
-----
Max Area = 3.5*3.5 = 12.25 sq. units
========================================
Cheers,
Stan H.
==============