SOLUTION: How much of a 50% alcohol solution should we mix with 10 gallons of a 35% solution to get a 40% solution?
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Question 460215
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How much of a 50% alcohol solution should we mix with 10 gallons of a 35% solution to get a 40% solution?
Answer by
checkley79(3341)
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.50x+.35*10=.40(10+x)
.50x+3.5=4+.40x
.50x-.40x=4-3.5
.10x=.5
x=.5/.10
x=5 gallons of 50% are required,
Proof:
.50*5+.35*10=.40(10+5)
2.5+3.5=.4*15
6=6