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--------------- QUESTION FOLLOWS --------------------------
if 4 -3a=7-2(2a+5) evaluate a^2+7a
Please I NEED HELP
(-2x^3+x-1)-(-x^2+x-3)
(2x^2+5x-3)-(3x^3+2x-5)
a ship traveling east at 25mph is 10mi from a harbor when another ship leaves the harbor traveling east at 35mph. How long does it take the second ship to catch up.?
You can put this solution on YOUR website! if 4 -3a=7-2(2a+5) evaluate a^2+7a
4-3a=7-4a-10
-3a+4a=7-10-4
a=-7
a^2+7a= 49-49
=0
.....
(-2x^3+x-1)-(-x^2+x-3)
-2x^3+x-1 +x^2-x+3
-2x^3+x^2+3
(2x^2+5x-3)-(3x^3+2x-5)
-3x^3+2x^2+3x+5
a ship traveling east at 25mph is 10mi from a harbor when another ship leaves the harbor traveling east at 35mph. How long does it take the second ship to catch up.?
catch up distance = 10 miles
catchup speed = 35 -25 = 10 mph
catchup time = catchup distance / catch up speed
10/10
=1 hour to catch up
