SOLUTION: PLEASE HELP ME PLEASE IM SOOOO STUCK ON THIS :) THANK YOU: AN AIRCRAFT FLEW 4 HOURS WITH THE WIND. THE RETURN TRIP TOOK 5 HOURS AGAINST THE WIND. IF THE SPEED OF OF THE PLANE IN

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Question 459758: PLEASE HELP ME PLEASE IM SOOOO STUCK ON THIS :) THANK YOU:
AN AIRCRAFT FLEW 4 HOURS WITH THE WIND. THE RETURN TRIP TOOK 5 HOURS AGAINST THE WIND. IF THE SPEED OF OF THE PLANE IN STILL AIR IS 384 MILES PER HOUR MORE THAN THE WIND SPEED, FIND THE SPEED OF THE WIND SPEED AND THE SPEED OF THE PLANE IN STILL AIR,
THANK YOU!!!
Found 3 solutions by richwmiller, amoresroy, stanbon:
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
Stop shouting. Is the airplane too loud?

Answer by amoresroy(361) About Me  (Show Source):
You can put this solution on YOUR website!
AN AIRCRAFT FLEW 4 HOURS WITH THE WIND. THE RETURN TRIP TOOK 5 HOURS AGAINST THE WIND. IF THE SPEED OF OF THE PLANE IN STILL AIR IS 384 MILES PER HOUR MORE THAN THE WIND SPEED, FIND THE SPEED OF THE WIND SPEED AND THE SPEED OF THE PLANE IN STILL AIR,
Let x = speed of plane in still air
y = wind speed
Distance = Distance
4 (x+y) = 5(x-y)
4x +4y = 5x-5y
x = 9y
--------------------------
where x = 384+y
By substitution you get
9y = 384+y
8y = 384
y = 48
x = 384+48
x = 432
The wind speed is 48 miles per hour while the speed of plane in still air is 432 miles per hour.

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
AN AIRCRAFT FLEW 4 HOURS WITH THE WIND. THE RETURN TRIP TOOK 5 HOURS AGAINST THE WIND. IF THE SPEED OF OF THE PLANE IN STILL AIR IS 384 MILES PER HOUR MORE THAN THE WIND SPEED, FIND THE SPEED OF THE WIND SPEED AND THE SPEED OF THE PLANE IN STILL AIR,
------------------
With wind DATA:
time = 4 hrs ; distance = x miles ; rate = d/t = x/4 mph
----------------------------------
Against wind DATA:
time = 5 hrs ; distance = x miles ; rate = d/t = x/5 mph
------------------
Let wind speed be "w".
Let speed of the plane in still air = "p".
---
Equation:
p + w = x/4
p - w = x/5
p = w + 384
-----------------------
Substitute for "p" and solve for w and x:
w + 384 + w = x/4
w + 384 - w = x/5
-------
2w + 384 = x/4
384 = x/5
x = 1920 miles
----
Solve for "w":
2w + 384 = 1920/4
2w = 96
wind speed = 48 mph
---
Solve for "p":
p = w + 384
plane speed in still air = 48+384 = 432 mph
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Cheers,
Stan H.
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