SOLUTION: Please help me! I have to solve by factoring. 3 equations. 1. x^2 + x = 6 2. x^2 + 7x -18 = 0 3. 2x^2 -x-3=0

Algebra ->  Rational-functions -> SOLUTION: Please help me! I have to solve by factoring. 3 equations. 1. x^2 + x = 6 2. x^2 + 7x -18 = 0 3. 2x^2 -x-3=0      Log On


   



Question 459751: Please help me! I have to solve by factoring. 3 equations. 1. x^2 + x = 6
2. x^2 + 7x -18 = 0
3. 2x^2 -x-3=0

Answer by amoresroy(361) About Me  (Show Source):
You can put this solution on YOUR website!
1. x^2 + x = 6
Rearrange to get
x^2 + x - 6 = 0
(x+3)(x-2) = 0
So, x = -3
x = 2
--------------------------
2. x^2 + 7x -18 = 0
(x+9)(x-2) = 0
So, x = -9
x = 2
--------------------------
3. 2x^2 -x-3=0
(2x-3)(x+1) = 0
When 2x-3 = 0
x = 1.5
When x+1 = 0
x = -1
============================
Regards
Roy