SOLUTION: Write the slope-intercept equation for the line that passes through (-9, 9) and is perpendicular to -9x – 2y = 10 Please show all of your work

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Question 459714: Write the slope-intercept equation for the line that passes through (-9, 9) and is perpendicular to -9x – 2y = 10 Please show all of your work
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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Write the slope-intercept equation for the line that passes through (-9, 9) and is perpendicular to -9x – 2y = 10
:
Find the slope of the given equation, put it in the slope intercept form
-9x - 2y = 10
-2y = 9x + 10
y has to be positive, mult by -1
2y = -9x - 10
Divide by 2
y = -9%2F2x - 5
:
m1 = -9%2F2 is the slope
:
The slope relationship of perpendicular lines: m1*m2 = -1. Find m2
-9%2F2*m2 = -1
m2 = 2%2F9
:
Find the equation using y - y1 = m(x - x1)
m=2%2F9, x1=-9, y1=9
y - 9 = 2%2F9(x - (-9))
y - 9 = 2%2F9(x + 9)
y - 9 = 2%2F9x + 2
y = 2%2F9x + 2 + 9
y = 2%2F9x + 11