SOLUTION: AN AIRCRAFT FLEW 4 HOURS WITH THE WIND. THE RETURN TRIP TOOK 5 HOURS AGAINST THE WIND. IF THE SPEED OF OF THE PLANE IN STILL AIR IS 384 MORE THAN THE SPEED OF THE WIND, FIND THE SP

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: AN AIRCRAFT FLEW 4 HOURS WITH THE WIND. THE RETURN TRIP TOOK 5 HOURS AGAINST THE WIND. IF THE SPEED OF OF THE PLANE IN STILL AIR IS 384 MORE THAN THE SPEED OF THE WIND, FIND THE SP      Log On

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Question 459682: AN AIRCRAFT FLEW 4 HOURS WITH THE WIND. THE RETURN TRIP TOOK 5 HOURS AGAINST THE WIND. IF THE SPEED OF OF THE PLANE IN STILL AIR IS 384 MORE THAN THE SPEED OF THE WIND, FIND THE SPEED OF THE PLANE IN STILL AIR AND THE SPEED OF THE PLANE AGAINST THE WIND.
PLEASE HELP ME
Answer by jorel1380(3719) About Me  (Show Source):
You can put this solution on YOUR website!
4(x+x+384)=5(x+384-x)
4(2x+384)=5(384)
8x=384
x=48
The speed of the plane in still air is 384+48 mph, or 432 mph. The speed of the wind is 48 mph..