SOLUTION: factor the trinomials completely x^2+6x-27 4c^2+9c-28 Thank you from Minka

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Question 459463: factor the trinomials completely
x^2+6x-27
4c^2+9c-28
Thank you
from Minka
Found 2 solutions by MathLover1, richwmiller:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

1.
x%5E2%2B6x-27.........replace 6x with -3x%2B9x
x%5E2-3x%2B9x-27...group
%28x%5E2-3x%29%2B%289x-27%29
x%28x-3%29%2B9%28x-3%29

%28x%2B9%29%28x-3%29
2.
4c%5E2%2B9c-28.........replace 9c with -7c%2B16c
4c%5E2-7c%2B16c-28
4c%5E2%2B16c-7c-28.....group
%284c%5E2%2B16c%29-%287c%2B28%29
4c%28c%2B4%29-7%28c%2B4%29
%284c-7%29%28c%2B4%29


Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
x^2+6x-27
(x+9)*(x-3)
4c^2+9c-28
factors of -112 which add up to 9
16 -7
4c^2+16c-7c-28
4c*(c+4)-7(c+4)
(4c-7)*(c+4)